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8x^2+36x+28=0
a = 8; b = 36; c = +28;
Δ = b2-4ac
Δ = 362-4·8·28
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-20}{2*8}=\frac{-56}{16} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+20}{2*8}=\frac{-16}{16} =-1 $
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